q=by+Louis+de+Broglie++translated+by+Martin+Davidson.&searchType=standard&isFacet=true&view=standard&rows=10&sortWay=score&sortOrder=desc&curlibcode=BZFG&searchWay0=marc&logical0=AND
rows=10&curlibcode=BZFG&searchWay0=marc&logical0=AND
by Louis de Broglie translated by Martin Davidson.